Whether you are estimating on the spot or checking a result somebody else gave you, the snowman calculator is the quickest way to get from air temperature, snowman’s initial temperature, dens man, p, diameter of the small ball, diameter of the smaller ball, diameter of the smaller ball, diameter of the smaller ball, diameter of the smaller ball, diameter of the small ball, diameter of the snow-covered surface, i’m able to use …, length of the snow-covered surface, width of the snow-covered surface, required snow area, snow area, sin and snow cover thickness to diameter of the larger ball, diameter of the medium ball and diameter of the large ball.
What Is the Snowman Calculator?
The snowman calculator turns air temperature, snowman's initial temperature, dens man, p, diameter of the small ball, diameter of the smaller ball, diameter of the smaller ball, diameter of the smaller ball, diameter of the smaller ball, diameter of the small ball, diameter of the snow-covered surface, i'm able to use ..., length of the snow-covered surface, width of the snow-covered surface, required snow area, snow area, sin and snow cover thickness into diameter of the larger ball, diameter of the medium ball and diameter of the large ball.
It is a quick way to get from the numbers you have to the number you need, without setting up a spreadsheet or reaching for a formula.
How the Snowman Works
Each result follows from the ones before it, and the calculator shows every step, so a surprising answer can be traced back to the input that caused it.
Round your inputs to the precision you actually know, and keep more precision than that in the intermediate steps.
Getting a Result You Can Trust
Run the calculation twice with slightly different inputs. A sensible calculator moves its output in proportion; a wild change points to a unit or a decimal point problem in what you entered.
Write the inputs down next to the answer. It takes a moment and it is the difference between a number you can explain and one you cannot.
A Worked Example
Working through an example, with air temperature set to 10, snowman's initial temperature set to 5, dens man set to 2, the calculator returns snow area of 50, and snow area (snow area circ) of 3.14159, and mass of the snowman of 37,699.116. Substitute your own figures and the same steps produce the same kind of answer.
Frequently Asked Questions
What do I need to work out diameter of the larger ball?
Enter air temperature, snowman's initial temperature, dens man, p, diameter of the small ball, diameter of the smaller ball, diameter of the smaller ball, diameter of the smaller ball, diameter of the smaller ball, diameter of the small ball, diameter of the snow-covered surface, i'm able to use ..., length of the snow-covered surface, width of the snow-covered surface, required snow area, snow area, sin and snow cover thickness. The calculator then works through the relationship and reports diameter of the larger ball, diameter of the medium ball and diameter of the large ball.
What does the snowman actually calculate?
It takes air temperature, snowman's initial temperature, dens man, p, diameter of the small ball, diameter of the smaller ball, diameter of the smaller ball, diameter of the smaller ball, diameter of the smaller ball, diameter of the small ball, diameter of the snow-covered surface, i'm able to use ..., length of the snow-covered surface, width of the snow-covered surface, required snow area, snow area, sin and snow cover thickness and converts them into diameter of the larger ball, diameter of the medium ball and diameter of the large ball using the standard relationship for this problem. Each step is applied in turn, so every output is traceable back to the numbers you typed in.
How should I enter air temperature?
Use the value you actually have, in the unit shown next to the field. Enter every value in the same unit system. The calculator assumes the figures you supply are consistent, so it cannot correct a mistake that happens before the calculation starts.
Is the answer exact?
It is as exact as the formula and the inputs allow. The method itself is the standard one for this problem, so the only sources of error are the figures you enter and the precision you ask for.
Why does a small change in one value move the answer so much?
That happens when an output depends on a ratio, because dividing by a small number magnifies any change in it. Check the units first, then check whether the value you entered is in the range the relationship was designed for.